12x^2-260x+966=0

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Solution for 12x^2-260x+966=0 equation:



12x^2-260x+966=0
a = 12; b = -260; c = +966;
Δ = b2-4ac
Δ = -2602-4·12·966
Δ = 21232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{21232}=\sqrt{16*1327}=\sqrt{16}*\sqrt{1327}=4\sqrt{1327}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-260)-4\sqrt{1327}}{2*12}=\frac{260-4\sqrt{1327}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-260)+4\sqrt{1327}}{2*12}=\frac{260+4\sqrt{1327}}{24} $

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